Solve simultaneously, x+y=2 and 4y^2-x^2=11

(1) x + y = 2(2) 4y2 - x2 = 11
Rearrange (1) to x= 2-y & substitute x=2-y into equation (2)
Simplify the new equation to 3y2+4y-15 = 0, use quadratic formula or simplify to (3y-5)(y+3)=0 and solve to get
y1= 5/3 y2 = -3
Substitute the values of y1 and y2 into equation one and solve for the 2 values of x
y1= 5/3 x1= 1/3 y2 = -3 x2 = 5
Substitute answers for x and y back into the original equations to verify they are correct

NN
Answered by Nicholas N. Maths tutor

4266 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

When should you use the sine rule and when should you use the cosine rule?


Solve the simultaneous equations: 1) 3x+5y=14 and 2) -3y+10=x


What are the coordinates of the two turning points of the curve y = x^3+3x^2+3?


Work out the value of x and y in the parallelogram ABCD.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning