Prove algebraically that the difference between the squares of any two consecutive odd numbers is always a multiple of 8

(2n+3)^2-(2n+1)^2 4n^2+12n+9-4n^2-4n-1 8n+8 8(n+1), which is a multiple of 8

JG
Answered by Jordan G. Maths tutor

5404 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following equation 3(2x -1) = 4(x - 2)


A right-angle triangle has a hypotenuse of 8cm and an angle of 30 degrees. What is the opposite's length?


1. Find the value of the missing edge to 2 decimal places 2. Find the angle θ to 2 decimal places


factorise fully- 8y + 4y2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences