Find the points of intersection of the line y+x=8 and a circle with centre at (3,-2) and radius 5.
1 Circle Equation: (x-3)2+(y+2)2=52 2 Line Equation: y=-x+8Sub Equation 2 into 1(x-3)2+(10-x)2=25x2-13x+42=0(x-7)(x-6)=0x=7,x=6 Sub Values back into equation 2Points = (7,1)&(6,2)
JB
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