Find both roots of the following equation x^2 + 2x - 4 = 0

There are many methods available to solve this - let's use the quadratic formula in this case.We know the formula is x = (-b +- sqrt(b^2-4ac))/2a.Here a=1,b=2,c=4,Hence, we know that x = (-2 +- sqrt(4 - - 16))/2Let's simplify this to x = -1 +- sqrt(20)/2 = -1 +- sqrt(5)

AH

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Make "a" the subject of the following equation: 2b = (3a+4)/(c-a)


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Given: 𝑓(π‘₯) = π‘Žπ‘₯^3 + 𝑏π‘₯^2 βˆ’ 3 and 𝑓"(βˆ’2) = 0. If it is further given that the point (βˆ’3; 6) lies on the graph of 𝑓. Show that π‘Ž = 1/3 and 𝑏 = 2.


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