Solve the simultaneous equations: 2x - y = 1, 3x + y = 14
Make y the subject of equation 1:y = 2x - 1Substitute this value of y into equation 2:3x + (2x - 1) = 14Simplify:5x - 1 = 14Solve for x:x = 3Substitute this value of x into original equation:2(3) - y = 1Simplify and solve for y:6 - y = 1y = 6 - 1y = 5
SB
Related Maths GCSE answers
All answers ▸Jo wants to work out the solutions of x^2 + 3x – 5 = 0 She says, ‘‘The solutions cannot be worked out because x^2 + 3x – 5 does not factorise to (x + a)(x + b) where a and b are integers.’’ Is Jo correct?
A right-angled triangle has an angle of 30 degrees and its hypotenuse has a length of 9cm. Find the length of either of the triangle's other two sides.
Expand and Simplify (5x - 2y)^2
solve this equation: 4(x-5)=x+7