Complete the square on the equation (x^2)-4x-3

x2-4x-3 First factorise into squared form and expand.(x-2)2=x2-4x+4Balance the equations.x2-4x+4 needs to be x2-4x-3This leads to(x-2)2-4-3 to get rid of the +4 from factorising.Leaving finally(x-2)2-7As an extension could ask the student about minimum value of the curve

EM

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Jo wants to work out the solutions of x^2 + 3x – 5 = 0 She says, ‘‘The solutions cannot be worked out because x^2 + 3x – 5 does not factorise to (x + a)(x + b) where a and b are integers.’’ Is Jo correct?