Solve the simultaneous equations 2x + y = 8 and 3x + 2y = 14
We want to make the number in front of either x or y the same in both equationsSo we multiply the first equation by 2(2x x 2) + (y x 2) = (8 x 2)4x + 2y = 16We then subtract the second equation from our new one 4x + 2y = 16-3x +2y = 14x + 0 = 2So x = 2Substitute this into either equation(2 x 2) + y = 84 + y = 8y = 8 - 4 = 4So the answer is x = 2 and y = 4
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