Solve the simultaneous equations 2x + y = 8 and 3x + 2y = 14

We want to make the number in front of either x or y the same in both equationsSo we multiply the first equation by 2(2x x 2) + (y x 2) = (8 x 2)4x + 2y = 16We then subtract the second equation from our new one 4x + 2y = 16-3x +2y = 14x + 0 = 2So x = 2Substitute this into either equation(2 x 2) + y = 84 + y = 8y = 8 - 4 = 4So the answer is x = 2 and y = 4

RM
Answered by Roshene M. Maths tutor

3936 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

x is an integer such that ‎1≤x≤9, Prove that 0.(0x)recurring=x/99


What is the lowest common multiple and the highest common factor of 120 and 150?


Solve x^2+6x-7 by completing the square.


Write 825 as a product of its prime factors.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences