Why does magnetic field do no work on an electric charge?

There is a qualitative and a quantitative way to show that the magnetic field does no work on electric charges. The qualitative description requires a picture; essentially, one looks at the circular orbits of moving particles in a magnetic field and notices that the force on the charge is always central (perpendicular to the direction of movement). If the force is central then F.dx is always zero and there can be no work done by the field. Interestingly, this is the case for any central force (e.g. gravity).
Quantitatively, one can prove this statement by looking at the equation describing the force on a charge due to a magnetic field, the lorentz force formula F = q(Ev x B), we can assume no electric field to be present so the equation becomes F = q(v x B). Similarly, the rate of work done can be found to be P = F.thus for forces due to magnetic fields we find P = q(v x B).v. But this is equal to zero because x is perpendicular to both and B, and hence the dot product is zero.

JS
Answered by Jergus S. Physics tutor

3544 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

An ideal gas at a temperature of 22 C is trapped in a metal cylinder of volume 0.2 m^3 at a pressure of 1.6x10^6 Pa. The gas has a molar mass of 4.3 x 10^(-2) kg mol^(-1). Calculate the density of the gas in the cylinder.


What is the function of the control rods in the entire fission reactor proccess?


How can a car be changing velocity yet not changing speed?


A sample of pure gold has a density of 19300 kgm^-3. If the density of a gold nucleus is 1.47x10^17Kgm^-3, discuss what this implies about the structure of the gold atom. [4 marks]


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning