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Let f(x) = px^2 + qx - 4p, where p is different than 0. Showing your working, find the number of roots for f(x) = 0.

Δ = b² - 4ac = q² - 4p (-4p) = q² + 16p²p different than 0 => 16p² greater than 0 onlyq² greater or equal to 0q² + 16p² > 0 => f has two (2) roots

Answered by Hristo S. • Maths tutor

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