Let f(x) = px^2 + qx - 4p, where p is different than 0. Showing your working, find the number of roots for f(x) = 0.
Δ = b2 - 4ac = q2 - 4p (-4p) = q2 + 16p2p different than 0 => 16p2 greater than 0 onlyq2 greater or equal to 0q2 + 16p2 > 0 => f has two (2) roots
HS
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