given that (x+8)^2-62=ax^2+bx+c find the values of a,b and c (3 marks)

For this question, the main component of the equation we need o look at is (x+8)^2. We know that (x+8)^2 is the same as (x+8)(x+8). First we have to expand these brackets. For his I make small table to ensure that I expand this correctly. So once we have expanded this fracker- we should get x^2+8x+8x+64. However this is only when we expand the brackets, we cannot forget about the -62 in the equation.So putting it all together our solved equation should be: x^2+16x+64-62this can be simplified to x^2+16x+2 - allowing us to answer the question is the asked form