Prove that the square of an odd number is always 1 more than a multiple of 4
(2n+1)2 = (2n+1)(2n+1)
Use FOIL method= 4n2+2n+2n+1= 4n2+4n+1= 4(4n+n)+1
4n+n is just a number, therefore proved
DH
(2n+1)2 = (2n+1)(2n+1)
Use FOIL method= 4n2+2n+2n+1= 4n2+4n+1= 4(4n+n)+1
4n+n is just a number, therefore proved
