Find the tangent to the curve y=x^3+3 at the point x=1.

1. Differentiate the Equation of the curve to find the gradient: y'=3x^2

2. The gradient of the tangent is found by substituting x=1 into y'=3x^2: Gradient of tangent=3

3. Now we must find out the co-ordinates of the point. These are (x=1y=1^3+3) = (1,4).

4. Now to find out the equation of the tangent, substitute x=1, y=4 and m=3 into y=mx+c to get c=1, (the y-intercept)

5. This gives the tangential equation as y=3x+1.

SK
Answered by Sevenia K. Maths tutor

4190 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How to differentiate a bracket raised to a power i.e. chain rule


Using the "complete the square" method, solve the following x^2 +4x - 21 =0


Given a table showing grouped data and the frequency of each class, find the median Q2


Find the equation of the tangent to the curve y=x^3 + 4x^2 - 2x - 3 where x = -4


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences