How can you factorise quadratics with a an x^2 coefficient higher than one?
If we take an example question such as 20x2 - 130 x = -20020x2 - 130 x = -200 Divide by 10 to simplify2x2 - 13x = -20 Take all of the terms to the left2x2 - 13x +20 = 0 Now use this technique. Multiply a and c to get 40 Then try to find two numbers that multiply to get 40 and add to get b (-13) This would be -8 and -5Now factorise 2x2 -8x -5x +20 = 0 2x (x-4) -5 (x-4) = 0(2x-5) (x-4) =0
VT
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