Write 2-(x+2)/(x-3)-(x-6)/(x+3) as a single fraction of ax+b/x^2-9. What is a and b?

Multiply according terms so that the denominators are the same for all fractions. [2(x-3)(x+3)/(x-3)(x+3)]-[(x+2)(x+3)/(x-3)(x+3)]-[(x-6)(x-3)/(x-3)(x+3)]Expand out the brackets: 2x²-18-x²-5x-6-x²+9x+18/x²-9Simplify: 4x-42/x²-9 Answer: a=4 b=-42