Write 2-(x+2)/(x-3)-(x-6)/(x+3) as a single fraction of ax+b/x^2-9. What is a and b?
Multiply according terms so that the denominators are the same for all fractions. [2(x-3)(x+3)/(x-3)(x+3)]-[(x+2)(x+3)/(x-3)(x+3)]-[(x-6)(x-3)/(x-3)(x+3)]Expand out the brackets: 2x2-18-x2-5x-6-x2+9x+18/x2-9Simplify: 4x-42/x2-9 Answer: a=4 b=-42
NS
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