Solve the simultaneous equations: 5x + y = 21, x - 3y = 9

Call '5x + y = 21' equation 1 and 'x - 3y = 9' equation 2. To solve this, we need the coefficients of x in both equations to be the same or the coefficients of y in both equations to be the same.
Method 1 - solving for y firstMultiply equation 2 by 5 to get:5x - 15y = 45 (call this equation 3)Now we are going to take equation 1 away from equation 3: 5x - 15y = 45 - 5x + y = 21 which becomes: -16y=24Solve for y:y=-24/16 =-3/2Sub this value into equation 1 to solve for x:5x + (-3/2) = 215x = 45/2x= 9/2

BI
Answered by Basil I. Maths tutor

5015 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The functions f and g are such that f(x)=5x+2 and g(x)=-x-4. a) Find fg(x). b) Find ff(x). c) Solve fg(x) = ff(x).


Question: What proportion of the clock is the area covered when the time is 12:10? (Here the question should indicate the time stated and shade in the proportion of the clock to be computed.)


Solve the simultaneous equations: 5x+y=21, x-3y=9


In a box, there is 1 more green pens than black pens. The probability of taking 2 black pens is 0.2 . How many pens are in the box?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning