Solve the simultaneous equations: 5x + y = 21, x - 3y = 9

Call '5x + y = 21' equation 1 and 'x - 3y = 9' equation 2. To solve this, we need the coefficients of x in both equations to be the same or the coefficients of y in both equations to be the same.
Method 1 - solving for y firstMultiply equation 2 by 5 to get:5x - 15y = 45 (call this equation 3)Now we are going to take equation 1 away from equation 3: 5x - 15y = 45 - 5x + y = 21 which becomes: -16y=24Solve for y:y=-24/16 =-3/2Sub this value into equation 1 to solve for x:5x + (-3/2) = 215x = 45/2x= 9/2

BI
Answered by Basil I. Maths tutor

4872 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Express x*2 + 10x - 3 in the form (x+p)*2 + q


solve the inequality x^2-4x+4>0


Simplify 7 × e × f × 8


Solve the simultaneous equations 2x + 7y = 15 and 3x + 6y = 21


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning