Write down the value of 27^(-2/3)

We are trying to solve 27^-2/3. Firstly, using the index rule a^xy= (a^x)^y, this can be rewritten as (27^1/3)^-2. Lets tackle the value inside the bracket first: 27^1/3 means the cube root of 27, and so is 3 (as 3³ = 27). Therefore we have 3^-2. Any value to the power of a negative becomes one over that value. As a result, we have 1/(3²) = 1/9