Write down the value of 27^(-2/3)

We are trying to solve 27-2/3. Firstly, using the index rule axy= (ax)y, this can be rewritten as (271/3)-2. Lets tackle the value inside the bracket first: 271/3 means the cube root of 27, and so is 3 (as 33 = 27). Therefore we have 3-2. Any value to the power of a negative becomes one over that value. As a result, we have 1/(32) = 1/9

Answered by Matt L. Maths tutor


See similar Maths GCSE tutors
Illustration of a video tutorial

Need help with Maths?

One to one online tuition can be a great way to brush up on your Maths knowledge.

Have a Free Meeting with one of our hand picked tutors from the UK’s top universities

Find a tutor

Related Maths GCSE answers

All answers ▸

There are 11 pens in a box. 8 are black and 3 are red. Two pens are taken out at random without replacement. Work out the probability that the two pens are the same colour.

Solve the simultaneous equations: 2x + 3y = 5 and 3x + 4y = 12

Solve the following simultaneous equations: x^2 + y^2 = 29 and y - x =3

Rationalise the denominator of 6/√3 and simplify your answer.

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2022

Terms & Conditions|Privacy Policy