I don't fully understand the purpose of integration. Could you please explain it to me?

I have written "… " where I would imagine the student is replying. I have then provided prompts assuming that the student did not come up with the answer straight away. Integration can be useful in lots of areas like mechanics (finding velocities/accelerations), probability or simply for calculating areas of strange shapes. Would you like to see an example? Imagine you're a farmer and you want to know how much food your trough can hold. This is what it would look like (draw a trough). As it's a prism, you could calculate its volume by multiplying the area of its cross-section by its length. What shape could you use to describe the cross-section? A parabola, yes! Now say we wanted to calculate the area of this cross-section. How might we go about it? … Why don't you try drawing the shape on a graph and shading the region that describes the trough's cross-section? … Does that look like the area under a parabola (eg:-x^2+4)? Ok, do you remember calculating the area under a parabola in class? Let's take a look at your notes... Here it says that the integral of $x^n= x^{n+1}/(n+1)+C$. Could you remind me how this was obtained? (Either student gives an understanding of the relationship between differentiation and integration, or I will describe it if I feel it's necessary). Great, so how could you apply this to our problem? I see you've noted that $n=2$ for the parabola and that the limits of integration are -2 to 2. That's good! Could you give me an exact answer? Yes, 32/3 is correct!Example answer:First solve -x^2+4=0 to get x=2,-2. This tells us to integrate -x^2+4 from -2 to 2. So we obtain -2^3/3+42-(2^3/3-42)=-16/3+16=32/3.

RL
Answered by Rebecca L. Maths tutor

3008 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given y = 2x(x2 – 1)5, show that (a) dy/dx = g(x)(x2 – 1)4 where g(x) is a function to be determined. (b) Hence find the set of values of x for which dy/dx > 0


Given that: 2tanθsinθ = 4 - 3cosθ , show that: 0 = cos²θ - 4cosθ + 2 .


Find the area between the curves C_1, C_2 and the lines x=0 and x=1, where C_1 is the curve y = x^2 and C_2 is the curve y = x^3.


A curve C is mapped by the equation ( 1+x)(4-x). The curve intersects the x-axis at x = –1 and x = 4. A region R is bounded by C and the x-axis. Use calculus to find the exact area of R.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning