Integrate, with respect to x, xCos3x

Integration by parts:
u = x u' = 1v' = Cos3x v = (Sin3x)/3 + c
So, ∫xCos3x= (XSin3x)/3 - ∫(Sin3x)/3 dx= (XSin3x)/3 - 1/3( - (Cos3x)/3) + c = (XSin3x)/3 + (Cos3x)/9 + c

Answered by Maths tutor

3573 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

When do we use the quadratic formula, and when the completing the square method?


Given y=x^2(1+4x)^0.5, show that dy/dx=2x(5x+1)/((1+4x)^0.5)


Can you prove to me why cos^2(X) + sin^2(X) = 1?


Express 4x/(x^2-9) - 2/(x+3) as a single fraction in its simplest form.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences