Integrate, with respect to x, xCos3x

Integration by parts:
u = x u' = 1v' = Cos3x v = (Sin3x)/3 + c
So, ∫xCos3x= (XSin3x)/3 - ∫(Sin3x)/3 dx= (XSin3x)/3 - 1/3( - (Cos3x)/3) + c = (XSin3x)/3 + (Cos3x)/9 + c

Answered by Maths tutor

3745 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The variables x and y are related by y = 5^x. How do I find the value of x when y is set to 15?


How do you integrate by parts?


A particle of mass 0.8 kg moving at 4 m/s rebounds of a wall with coefficient of restitution 0.3. How much Kinetic energy is lost?


Differentiate y= 2^x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences