Integrate, with respect to x, xCos3x
Integration by parts:
u = x u' = 1v' = Cos3x v = (Sin3x)/3 + c
So, ∫xCos3x= (XSin3x)/3 - ∫(Sin3x)/3 dx= (XSin3x)/3 - 1/3( - (Cos3x)/3) + c = (XSin3x)/3 + (Cos3x)/9 + c
Related Maths A Level answers
All answers ▸What is the integral of 2x^5 - 1/4x^3 - 5
How would you express (11+x-x^2)/[(x+1)(x-2)^2] in terms of partial fractions?
Find the total area enclosed between y = x^3 - x, the x axis and the lines x = 1 and x= -1 . (Why do i get 0 as an answer?)
What is the differential of y =sin(2x)?