Integrate, with respect to x, xCos3x

Integration by parts:
u = x u' = 1v' = Cos3x v = (Sin3x)/3 + c
So, ∫xCos3x= (XSin3x)/3 - ∫(Sin3x)/3 dx= (XSin3x)/3 - 1/3( - (Cos3x)/3) + c = (XSin3x)/3 + (Cos3x)/9 + c

Answered by Maths tutor

4081 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve is defined by the equation y^2 - xy + 3x^2 - 5 = 0. Find dy/dx.


7^6 x 7^3


The curve C has equation ye^(-2x) = 2x + y^2. Find dy/dx in terms of x and y.


How do I simplify (1 / [1 + cos(x) ] ) + (1 / [1 - cos(x) ] )?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning