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Find the area contained under the curve y =3x^2 - x^3 between 0 and 3

Equation of curve is: y = y =3x² - x³To find area need to integrate between 0 and 3So integrating each term gives x³ - x⁴/4 + cThen sub in the limits [(3³- 3⁴/4) - (0³ - 0⁴/4)] = 27-81/4 = 27 - 20.25 = 6.75

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Find the area contained under the curve y =3x^2 - x^3 between 0 and 3

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