Find the area contained under the curve y =3x^2 - x^3 between 0 and 3
Equation of curve is: y = y =3x2 - x3To find area need to integrate between 0 and 3So integrating each term gives x3 - x4/4 + cThen sub in the limits [(33 - 34/4) - (03 - 04/4)] = 27-81/4 = 27 - 20.25 = 6.75
JR
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