Solve sec(x)^2-2*tan(x)=4 for 0<=x<=360

We know sin(x)^2+cos(x)^2=1Dividing by cos(x)^2: tan(x)^2+1=sec(x)^2Substitute into the Equation and Rearrange to get: tan(x)^2-2*tan(x)-3=0Let y = tan(x): y^2-2y-3=0Factorising: (y-3)(y+1)=0so y = 3 and y = -1 are solutionsCase 1 (y=3):tan(x) = 3Using Calculator: x = 71.565... and since tan repeats every 180 degrees, 251.565... is also a solutionCase 2 (y=-1):tan(x) = -1Using Calculator: x = -45, but this is outside of the region so using the 180 rule twice, we get two more solutions at x = 135 and 315Thus we have 4 solutions

MR
Answered by Mukesh R. Maths tutor

4002 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate (2^x)(5x^2+5x)^2.


Find and classify all the stationary points of the function f(x) = x^3 - 3x^2 + 8


y = 2/x^3 find and expression for dy/dx


Find the coordinates of the point of intersection between the line L:(-i+j-5k)+v(i+j+2k) and the plane π: r.(i+2j+3k)=4.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning