A function is defined by f(x)= e^(x^2+4), all real x. Find inverse of f(x) and its domain.

Let f(x)=y: y = e^(x2+4); To find the inverse of a function, you need to find x in terms of y. In this case, you need to bring the exponent to the base. So in order to bring x2+4 from the power, take natural log of both sides so: ln(y) = ln(e^(x2+4)); ln(e^(a)) = a, where a is some function. This means that: ln(y) = x2+4; Now that x is a base, the algebra becomes simple. Isolate x; x2 = ln(y) - 4; Simplify; x = sqrt(ln(y) - 4); This is the inverse. However, to use the same terms as the original function let x = y and y = x, so; y = sqrt(ln(x)-4).

EC

Related Maths A Level answers

All answers ▸

integrate cos^2(2x)sin^3(2x) dx


Find the equation of the tangent to the curve y = (5x+4)/(3x -8) at the point (2, -7)


Given f(x)=2x^3 - 2x^2 + 8x, find f'(x) and f"(x).


How do you integrate by parts?