Solve the simultaneous equations, make sure to show clear algebraic working: 3x + 5y = 14, 4x + 3y = 4

3x + 5y = 14 (times this entire equation by 3) --> 9x + 15y = 42 4x + 3y = 4 (times this entire equation by 5) --> 20x + 15y = 20Now both of the simultaneous equations have 15y, so you can subtract the second from the first to cancel out the Ys. This will leave you with only Xs so you can work out what the X constant equals. SUBTRACT: -11x + 0y = 22 (therefore -11x =22) 22/-11 = -2 x = -2 You can now substitute x into either of the original equations to work out the Y constant. (e.g. substitute into 1st equation) --> 3(-2) + 5y = 14. Therefore, -6 + 5y = 14 and you can work out that 5y = 20 (I did this by subtracting -6 from both sides). Divide both sides by 5 Y= 4, X = -2Bonus question! Write down the coordinates of the point of intersection of the two lines whose equations are: 3x + 5y = 14 and 4x + 3y = 4 (-2, 4)