Solve this simultaneous equations, clearly showing all of your workings: x^2 + 2y =9, y - x = 3

Equation 1: x2 + 2y = 9Equation 2: y - x = 3
Rearrange equation 2: y = 3 + x
Substitute y = 3 + x into equation 1x2 + 2(3 + x) = 9x2 + 6 + 2x = 9x2 + 2x - 3 = 0(x + 3)(x - 1) = 0so x = 1 and -3
substitute x = 1 into rearranged equation 2y = 3 + 1y = 4
substitute x = -3 into rearranged equation 2y = 3 - 3y = 0
So when x = -3, y= 0and when x = 1, y = 4

EJ
Answered by Ella-May J. Maths tutor

2263 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Make a the subject of the formula f=(a+1)/2


Factorise x^2 - 8x - 20


How do I find out the equation of a line?


Solve 5 < x² + 1 < 10


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences