Explain why the first ionisation energy of sulphur is lower than that of phosphorus.

The general trend is that the first ionisation energies increases across the period from Na to Ar. But the first ionisation energy of sulphur is lower than phosphorus because the electronic configuration is less stable. Like when you get on the bus, you would sit on whatever seat you can where you don’t have to sit next to someone until all of the free two-seats are used up. The same is with electrons - they fit into the orbitals one at a time until the only orbitals available are ones with electrons already in them. There is extra repulsion between electrons when two fit into the same orbital. The electronic configuration of phosphorus (3p3) means the electrons are in a 'maximum unpairing' configuration, which is very stable. The extra electron of sulphur (3p4) is added to an orbital which already contains an electron and the repulsion between these two electrons makes it easier to remove this electron and therefore the first ionisation energy is lower.

LR
Answered by Lana R. Chemistry tutor

13723 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

What's added to Ethanoyl Chloride to make Methyl Ethanoate? Draw out the mechanism for this reaction. Why is this preferred to esterification?


Give and explain 2 of the anomalous properties of ice caused by hydrogen bonding (3)


Explain trend in why the ionisation energies increase across the period


Write an equation for the incomplete combustion of dodecane to produce gaseous products only.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning