Explain why the first ionisation energy of sulphur is lower than that of phosphorus.

The general trend is that the first ionisation energies increases across the period from Na to Ar. But the first ionisation energy of sulphur is lower than phosphorus because the electronic configuration is less stable. Like when you get on the bus, you would sit on whatever seat you can where you don’t have to sit next to someone until all of the free two-seats are used up. The same is with electrons - they fit into the orbitals one at a time until the only orbitals available are ones with electrons already in them. There is extra repulsion between electrons when two fit into the same orbital. The electronic configuration of phosphorus (3p3) means the electrons are in a 'maximum unpairing' configuration, which is very stable. The extra electron of sulphur (3p4) is added to an orbital which already contains an electron and the repulsion between these two electrons makes it easier to remove this electron and therefore the first ionisation energy is lower.

LR
Answered by Lana R. Chemistry tutor

17109 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

State and explain the difference in base strength between phenylamine and ammonia.


What is the difference between 'Electrospray Ionisation' and 'Electron Impact' during the ionisation stage in a mass spectrometer?


What is the difference between structural isomers and stereoisomers?


Consider the following reaction: C2H4 + HBr -> ?. a) What is the product of the reaction? Name the compound and give the structural formula. b) What is the type of the reaction? c) Draw a reaction mechanism.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning