How do you find the distance a ball travels if fired at speed u and angle theta from the ground?

From a right angled triangle with hypotenuse u and angle theta, we see the horizontal speed is (u cos theta) and the initial vertical speed is (u sin theta). As the ball moves in a symmetric parabola, it hits the ground with vertical speed (-u sin theta).Therefore, the ball must be in the air for (2 u sin theta / g) seconds, so it travels a distance of (2 u^2 sin theta cos theta / g). This can be simplified to (u^2 sin (2 theta) / g).

DB
Answered by Douglas B. Maths tutor

2551 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How to do the product rule for differentiation


Given that cos(x) = 1/4, what is cos(2x)?


The line l1 has equation 4y - 3x = 10. Line l2 passes through points (5, -1) and (-1, 8). Determine whether the lines l1 and l2 are parallel, perpendicular or neither.


Prove by induction that the nth triangle number is given by n(n+1)/2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences