Can you explain how to find straight line equations?
Straight line equations always come in the form y=mx+c, where m is the gradient of the line (how steep it it) and c is the point where the line crosses the y axis (the y intercept).If you are given two points say 1 - (2, -4) and 2 - (6, 8) we can find the equation of the line that runs through them.First we find the gradient - this is the change in y over the change in x, (y2 - y1) / (x2 - x1)Here this is (8- (-4)) / (6 -2) = 12/4 = 3Next we plug this into the form of the equation and use one of the points to find ceg using point 1, -4 = 3 x 2 + cwe then re arrange -4 - 6 = cTherefore c = -10Finally we use all the values we have found to create the straight line equation,y=3 x -10
JQ
Related Maths GCSE answers
All answers ▸The diagram shows a prism. The cross-section of the prism is an isosceles triangle. The lengths of the sides of the triangle are 13 cm, 13 cm and 10 cm. The perpendicular height of the triangle is 12 cm. The length of the prism is 8 cm. Work out the total
What is the simplest form of the fraction (8a^2+10ab)/(12a+15b)?
y is proportional to x^2. When y=45, x=3. Find a formula for y in terms of x.
How do function transformations work?