Find the tangent to the curve y=x^2 +2x at point (1,3)

In order to find the gradient we need to differentiate d/Dx = 2x + 2using our point, the gradient is 4using y = mx+cy = 4x +cusing our pointsy= 4x - 1

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Answered by Diana W. Maths tutor

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What is calculus?


Integrate the natural logarithm of x (ln x) with respect to x


Simplify: (3x+8)/5 > 2x + 1


a) Integrate ln(x) + 1/x - x to find the equation for Curve A b) find the x coordinate on Curve A when y = 0.


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