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Find the tangent to the curve y=x^2 +2x at point (1,3)

In order to find the gradient we need to differentiate d/Dx = 2x + 2using our point, the gradient is 4using y = mx+cy = 4x +cusing our pointsy= 4x - 1

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Find the tangent to the curve y=x^2 +2x at point (1,3)

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Find the tangent to the curve y=x^2 +2x at point (1,3)

Related Maths A Level answers

Using the Quotient rule, Find dy/dx given that y = sec(x)

Differentiate: 2(x^2+2)^3

Solve e^(2x) = 5e^(x) - 6, giving your answers in exact form

Find the stationary points of the curve y=2*x^3-15*x^2+24*x+17. Determine whether these points are maximum or minimum.

Find the stationary points of the curve y=2x^3-15x^2+24*x+17. Determine whether these points are maximum or minimum.