Find the area between the curve y = 8 + 2x - x^2 and the line y = 8 - 2x.

First sketch the curve and the line, noting down where they intersect each axis.area under y = 8 + 2x - x2 is given by the integral between 0 and 4 of (8 + 2x - x2) dx.area under line is given by the integral between 0 and 4 of (8-2x) dx. It's easier to do this than using the formula for area of a triangle!!So total area:area = integral between 0 and 4 of (8 + 2x - x2) dx - integral between 0 and 4 of (8-2x) dxarea = integral between 0 and 4 of (8 + 2x - x2 - (8-2x))dx Note we can combine the two integrals!!area = integral between 0 and 4 of (4x - x2) dxarea = [2x2 - x3/3]40 = 32/3

Answered by Maths tutor

4604 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Is a line ax+by+c=0 tangent to a circle?


Solve the following equation: 5x - 1 = 3x + 7


Given y=x^2(1+4x)^0.5, show that dy/dx=2x(5x+1)/((1+4x)^0.5)


Solve the following equation by completing the square: x^2 + 6x + 3 = 0.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning