Find the area between the curve y = 8 + 2x - x^2 and the line y = 8 - 2x.

First sketch the curve and the line, noting down where they intersect each axis.area under y = 8 + 2x - x2 is given by the integral between 0 and 4 of (8 + 2x - x2) dx.area under line is given by the integral between 0 and 4 of (8-2x) dx. It's easier to do this than using the formula for area of a triangle!!So total area:area = integral between 0 and 4 of (8 + 2x - x2) dx - integral between 0 and 4 of (8-2x) dxarea = integral between 0 and 4 of (8 + 2x - x2 - (8-2x))dx Note we can combine the two integrals!!area = integral between 0 and 4 of (4x - x2) dxarea = [2x2 - x3/3]40 = 32/3

Answered by Maths tutor

4618 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the area beneath the curve with equation f(x) = 3x^2 - 2x + 2 when a = 0 and b = 2


Let y be a function of x such that y=x^3 + (3/2)x^2-6x and y = f(x) . Find the coordinates of the stationary points .


A curve has equation y = e^x + 10sin(4x), find the value of the second derivative of this equation at the point x = pi/4.


Given that y=π/6 at x=0 solve the differential equation,dy/dx=(e^x)cosec2ycosecy


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning