Find the area between the curve y = 8 + 2x - x^2 and the line y = 8 - 2x.

First sketch the curve and the line, noting down where they intersect each axis.area under y = 8 + 2x - x2 is given by the integral between 0 and 4 of (8 + 2x - x2) dx.area under line is given by the integral between 0 and 4 of (8-2x) dx. It's easier to do this than using the formula for area of a triangle!!So total area:area = integral between 0 and 4 of (8 + 2x - x2) dx - integral between 0 and 4 of (8-2x) dxarea = integral between 0 and 4 of (8 + 2x - x2 - (8-2x))dx Note we can combine the two integrals!!area = integral between 0 and 4 of (4x - x2) dxarea = [2x2 - x3/3]40 = 32/3

Answered by Maths tutor

4620 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

OCR C2 2015 Question 8: (a) Use logarithms to solve the equation 2^(n-3) = 18,000 , giving your answer correct to 3 significant figures. (b) Solve the simultaneous equations log2(x) + log2(y) = 8 & log2(x^2/y) = 7.


Find all values of x in the interval 0 ≤ x ≤ 2pi for 2sin(x)tan(x)=3


Starting from the fact that acceleration is the differential of velocity (dv/dt = a) derive the SUVAT equations.


A particle of mass m moves from rest a time t=0, under the action of a variable force f(t) = A*t*exp(-B*t), where A,B are positive constants. Find the speed of the particle for large t, expressing the answer in terms of m, A, and B.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning