What are the solutions to x^2+3x+2=0
Find two numbers that multiply to give 2 and add together to give 3: 1 and 2
Factorise: (x+2)(x+1)=0
The solutions are x= -2 and x= -1
Explanation: Brackets means you multiply, this means that when (x+2) and (x+1) multiply we get a product of 0. That means either (x+2)=0 or (x+1)=0, that's why there are two answers. If x= -2, then it becomes (-2+2)(-2+1)=(0)(1)=0. Try it the other way to check for yourself.
RA
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