Particle A mass 0.4kg and B 0.3kg. They move in opposite direction and collide. Before collision, A had speed 6m/s and B had 2m/s. After collision B had 3m/s and moved in opposite direction. Find speed of A after collision with direction and Impulse on B.
-> m1u1 + m2u2 = m1v1 + m2v22.4 - 0.6 = 0.4v1 + 0.90.9 = 0.4 v1v1 = 2.25m/s (direction unchanged)-> I = mv - mu= (0.3 x 3) - (0.3 x -2)= 1.5 Ns
SS
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