Differentiate the following: y=(7x^2+2)sinx
Differentiate using the product rule.Product rule: for y=uv , where u and v are functions of x, dy/dx=vdu/dx + udv/dxy=(7x2+2)sinx so u=(7x2+2) and v=sinx . By differentiating these functions:du/dx=14x and dv/dx=cosxnow we have expressions for u, v, du/dx and dv/dx, we can find dy/dx.Recall dy/dx=vdu/dx + udv/dx, by substituting our expressions:dy/dx=14xsinx +(7x2+2)cosx
ET
Related Maths A Level answers
All answers ▸Solving harder exponential equations, e.g. 5/[exp(x) + 6exp(-x)] - 1 = 0 . CORE MATHS.
Given the equation 0=5x^2+3xy-y^3 find the value of dy/dx at the point (-2,2)
What does it mean when I get a negative value when I do a definite integral?
What is 'completing the square' and how can I use it to find the minimum point of a quadratic curve?