Differentiate the following: y=(7x^2+2)sinx

Differentiate using the product rule.Product rule: for y=uv , where u and v are functions of x, dy/dx=vdu/dx + udv/dxy=(7x2+2)sinx so u=(7x2+2) and v=sinx . By differentiating these functions:du/dx=14x and dv/dx=cosxnow we have expressions for u, v, du/dx and dv/dx, we can find dy/dx.Recall dy/dx=vdu/dx + udv/dx, by substituting our expressions:dy/dx=14xsinx +(7x2+2)cosx

Answered by Maths tutor

2671 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find dy/dx where y= x^3(sin(x))


Show that (1 - cos(2x)) / (1 + cos(2x)) = sec^2(x) - 1


Differentiate y^3 + 3y^2 + 5


Integrate 1/u(u-1)^2 between 4 and 2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences