A curve has equation y = 7 - 2x^5. a) Find dy/dx. b) Find an equation for the tangent to the curve at the point where x=1.

a) The derivative dy/dx of the equation is: dy/dx = -10x4. If you don't remember this, revise Power Rule for derivatives.b) The equation of a line is given by y = mx + q. To find the tangent line at a point, we need: 1) Find the slope of the line by substituting that point in the equation of the derivative m = dy/dx (x=1) = -10. 2) Solve the system between the curve and the line at x=1 to find q. We find q=15. The equation of the line is therefore: y = -10x + 15

GC
Answered by Gianpiero C. Maths tutor

5956 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

By using the substitution, x = 2sin(y) find the exact value of integral sqrt(1/3(4-x^2)) dx with limits 0 and 1.


Using Pythagoras' theorem, show that sin^2(x)+cos^2(x)=1 for all x.


Find the tangent to the curve y = x^3 - 2x at the point (2, 4). Give your answer in the form ax + by + c = 0, where a, b and c are integers.


Integration question 1 - C1 2016 edexcel


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences