Solve: x^2+x-6=0
This is a quadratic equation. Its factorises to give: (x-2)(x+3)=0. Therefore there are two different solutions of this equation: x1=2 and x2=-3.
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Related Maths GCSE answers
All answers ▸How do you solve the following simultaneous equations? Equation 1: 2x + 3y = 13 Equation 2: 3x - y = 3
x^2 - 5x - 12 = 2, solve for x
Expand the brackets and simplify: 7(2x+3y)-x(14-y)
A right-angle triangle has sides AB, BC and CA with the right -angle between sides BC and CA. The angle between AB and BC is 24 degrees. The length of AB is 12m. How long is side BC?