The point P has coordinates (3, 4) The point Q has coordinates (a, b) A line perpendicular to PQ is given by the equation 3x + 2y = 7 Find an expression for b in terms of a

y = -3/2x + 7/2gradient = -3/2
gradient of perpendicular = 2/3
y = 2/3x + c
sub in given values of x and y to find c
y = 2/3x + 2
sub in a and b, so:
b = 2/3a + 2

Answered by Usamah A. Maths tutor


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