Solve Inx + In3 = In6

To solve Inx + In3 = In6 we must follow some basic log rules, 

logb(mn) = logb(m) + logb(n)

if we compare this with the left side of our equation, Inx + In3, we will set m = x and n = 3, 

mn is therefore 3x

this means that Inx + In3 is equivalent to In3x

So replacing that into our original equation:

In3x = In6

Take In of both sides

3x = 6

therefore x = 2

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