Solve Inx + In3 = In6

To solve Inx + In3 = In6 we must follow some basic log rules, logb(mn) = logb(m) + logb(n)if we compare this with the left side of our equation, Inx + In3, we will set m = x and n = 3, mn is therefore 3xthis means that Inx + In3 is equivalent to In3xSo replacing that into our original equation:In3x = In6Take In of both sides3x = 6therefore x = 2

EB
Answered by Ellie B. Maths tutor

11352 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is 'grouping' and how does it work?


Express root(125^x)/5^(2x-1) in terms of 5^a where a is an expression in terms of x.


How do I solve equations with modulus functions on both sides?


How do I integrate by substitution?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning