How to find out where 2 lines cross/simultaneous equations

If we have the 2 lines

line 1 - 3y=4x+2 and line 2 - 6y=7x+3

Firstly we would look for when the y's or x's are multiples of each other in this case the y's are multiples of each other as 3 is a multiple of 6.

Therefore we would times line 1 by 2 to become 6y=8x+4 -line 3

we then use line 2 and 3 as simultaneous equations to try and only have one variable in this case x.

line 2 - line 3 will give us     0=-x-1, so rearranging and moving x to the other side of the equation x=-1, then we put this back into any of the 3 lines to find out what y equals at this point.

So using line 1.. 3y= 4(-1)+2 so 3y=-2 so y=-2/3

so the lines 1 and 2 intersect at the point (-1,-2/3)

Answered by Jennifer L. Maths tutor

4099 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrate y=(x^2)cos(x) with respect to x.


(a) Find the differential of the the function, y = ln(sin(x)) in its simplest form and (b) find the stationary point of the curve in the range 0 < x < 4.


Given that d/dx(cosx)=-sinx show that d/dx(secx)=secx(tanx)


Find the equation for the tangent to the curve y^3 + x^3 + 3x^2 + 2y + 8 = 0 at the point (2,1)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy