Solve these simultaneous equations. 5x + 2y = 20 and x + 4y = 13.

(1) 5x + 2y = 20(2) x + 4y = 13Step 1: Eliminate x or y. We do this but making either the x or y terms the same, in this example, I will make the y terms the same, by multiplying the first equation by 2.(1) X 2 = 10x + 4y = 40. Let's call this equation (3).We can now take equation (2) away from (3).  10x + 4y = 40 _  x + 4y = 139x = 27Step 2: Divide both sides by 9 to get x on its own. x = 3.Step 3: Substitute x into equation (1) or (2).  For example, if you substitute it into equation (2) you get: 3 + 4y = 13.Step 4: Rearrange to find y. 4y = 10 y = 2.5Step 5: Check your answer by substiting your values for x and y into equation (1) or (2).Equation 1: 5(3) + 2(2.5) = 20 15 + 5 = 20The left hand side equals the right hand side, so you have found x and y!

AB
Answered by Andrew B. Maths tutor

7703 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you factorise a quadratic equation?


A plane flew from Frankfurt to Hong Kong. The flight time was 10hours 45minutes. The average speed was 852km/h. Work out the distance the plane flew.


Determine if the Following equality has real roots: (3*X^2) - (2*X) + 4 = (5*X^2) + (3*X) + 9, If the equation has real roots, calculate the roots for this equation.


How do i solve a system of 2 equations?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning