How do you integrate 3x^2 - 6x + 5 (wrt x)?
To integrate any term, add one to the power of x and divide the co-efficient (amount of x) by the new power, so xn becomes x(n+1)/(n+1).
Using this, 3x2 becomes 1x3, -6x becomes -3x2, and 5 becomes 5x.
Therefore, if we integrate 3x2-6x+5 with respect to x, we get x3-3x2+5x (+c, some arbitrary constant).
SC
Related Maths A Level answers
All answers ▸Find the turning point of the function y=f(x)=x^2+4x+4 and state wether it is a minimum or maximum value.
What is a logarithm?
Given that (2x + 11 )/(2x + 1)(x + 3) ≡ A /(2x + 1) + B /(x + 3) , find the values of the constants A and B. Hence show that the integral from 0 to 2 (2x + 11)/ (2x + 1)(x + 3) dx = ln 15.
Given that 4(cosec x)^2 - (cot x)^2 = k, express sec x in terms of k.