Differentiate y^3 + 3y^2 + 5
When you differentiate, you multiply by the old power and decrease the power by 1. If the expression has a constant in it, this differentiates to 0.
So the answer is 3y^(3-1) + (3x2)y^(2-1) + 0 = 3y^2 +6y
CH
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