MYTUTOR SUBJECT ANSWERS

62 views

How do I find the equation of a straight line?

Let's draw a line. It crosses the point (0,1), intercepting the y-axis (remember, y to the sky!) at 1 and the x-axis at the point (-2,0).

An equation tells us what a line looks like, it's a way of describing a line in a mathematical way. If we do it right, we can draw a line just by looking at the equation. Equations for straight lines are ususally given in the form y=mx+c - this tells us what y values do for different values of x. But what are m and c?

So, in order to find the equation for any straight line, we need two things: the gradient and the y-intercept. We call the y-intercept c and the gradient m. As soon as we know these two things, the rest is easy!

First step: finding the y-intercept - this is the simple bit, all you need to do is look at the y-axis and see where the line crosses it. In this case it is 1, so c=1.

Second step: finding the gradient - this requires a little bit more thought. All gradient means is the steepness of the line, so for every place the line moves to the right, how many places up does it go? In this case the line is not very steep at all and, in fact, you can see that for every place you move to the right it only goes up half a place up. Therefore m=0.5.

The tricky bit is over! Now comes the simple bit. All you have to do now is sub the values you've found for m and c back into the template equation, y=mx+c. So, if c=1 and m=0.5 then y=0.5x+1 - problem solved!

Dominique G. GCSE Classical Greek tutor, GCSE English Language tutor,...

2 months ago

Answered by Dominique, a GCSE Maths tutor with MyTutor

Still stuck? Get one-to-one help from a personally interviewed subject specialist

326 SUBJECT SPECIALISTS

£18 /hr

Calum C.

Degree: Economics (Bachelors) - Durham University

Subjects offered: Maths, Latin+ 1 more

Maths
Latin
Economics

“Hello there! I am Calum a current undergraduate Economics studnet at Durham university in my 1st year. If you would like to learn economics, maths or even latin from someone so eccentric and enthusiastic you will not be bored, ask me!”

MyTutor guarantee

£18 /hr

Brodie W.

Degree: Economics (Bachelors) - Durham University

Subjects offered: Maths, Economics

Maths
Economics

“About Me I am a second year economics student from St Aidan’s College, Durham University . Online tutoring is a new experience for me, but I am as keen to learn as I hope you are. I havepassion for all things economics and maths relate...”

£18 /hr

Ross G.

Degree: Mathematics (Masters) - Durham University

Subjects offered: Maths, Physics+ 2 more

Maths
Physics
Further Mathematics
.STEP.

“I am a maths student at Durham University. I love maths and I love studying it, both now and at A levels. I know that maths isn’t for everybody but I hope that in my tutorials I can help you learn the content and, maybe, you can learn ...”

MyTutor guarantee

About the author

£18 /hr

Dominique G.

Degree: Classics (Bachelors) - Cambridge University

Subjects offered: Maths, Latin+ 5 more

Maths
Latin
English Literature
English Language
Classical Greek
-Personal Statements-
-Oxbridge Preparation-

“Hi there! I'm Dommy, a third year undergraduate reading Classics at St. John's College, Cambridge and am currently on a year abroad at the University of Pavia, Italy. I am friendly and enthusiastic about learning and have previously t...”

You may also like...

Other GCSE Maths questions

Find the possible values of x for x^2 = 36-5x.

Solve the simultaneous equations 4x + 7y = 1 and 3x +10y = 15.

Solve the simultaneous equations: 5x + 3y = 9 and 7x - 2y = 25.

Simplify and solve the following equation: x^2 -8x +15=0

View GCSE Maths tutors

Cookies:

We use cookies to improve our service. By continuing to use this website, we'll assume that you're OK with this. Dismiss

mtw:mercury1:status:ok