Solve the simultaneous equations 2x + y = 7 and 3x - y = 8.

While there are several ways to solve this, in this particular case I would favour the method of elimination. Since the value of y is the same and they have opposite signs, we can add the equations together to eliminate the y value. This reads as 5x = 15 (add the x parts togther etc), as y + -y = 0. The divide by 5 to obtain x so we find x = 3. To find y, substitute the x value found into one of the equations and solve. 2(3) + y = 7. Thus y = 1. 

HB

Related Maths GCSE answers

All answers ▸

Factorise the following expression: 2(x^4) + 4(x^2) - 32(x^3)


The perimeter of an isosceles triangle is 16cm. The length of the base of the triangle is x+4 and that of the other two sides is x+3. Find the area of the triangle


Solve the simultaneous equations y = 5x^2 + 4x - 19 and y = 4x + 1


A right-angled triangle has an adjacent of (x + 1) and (x - 1). (a) Find the length of the hypotenuse in terms of x. (b) Explain why the triangle can't be an isoceles triangle.