Solve the simultaneous equations 2x + y = 7 and 3x - y = 8.

While there are several ways to solve this, in this particular case I would favour the method of elimination. Since the value of y is the same and they have opposite signs, we can add the equations together to eliminate the y value. This reads as 5x = 15 (add the x parts togther etc), as y + -y = 0. The divide by 5 to obtain x so we find x = 3. To find y, substitute the x value found into one of the equations and solve. 2(3) + y = 7. Thus y = 1. 

HB
Answered by Hannah B. Maths tutor

4620 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations “x^2+y^2=4” and “x=2-y”. What does this tell us about the circle centred on the origin, with radius 2, and the straight line with y-intercept 2 and gradient -1?


Solve the following fractional quadratic equation 14/(x^2-9)+1/(3-x)+(4-x)/(x+3)=7/(x+3), assuming x=/=+-3.


How can I know whether to multiply or add probabilities?


Expand (x+2)^2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning