How do I differentiate y=(4+9x)^5 with respect to x?

The method we use to differentiate this form of equation is called the chain rule.

The chain rule is dy/dx = dy/du x du/dx

We can rememeber the right way up of the terms on the right hand side by treating them as fracions and cancelling to give dy/dx.

To use the chain rule we need to define our u. In this form of question we choose what is inside the brackets.

Let u=4+9x, this means that y=u^5.

Then by normal rules of differentiation we differentiate y and u giving:

dy/du = 5u^4   and    du/dx = 9

Then we substitue these results into the chain rule formula giving:

dy/dx = 9 x 5u^4 = 45u^4

Then we substitute u=4+9x back in to get our final answer:

dy/dx = 45(4+9x)^4

JH

Related Maths A Level answers

All answers ▸

Given that y = (( 4x + 1 )^3)sin(2x), find dy/dx.


œintegrate xe4x in respect to x


Find the values of y such that log2(11y-3)-log2(3)-2log2(​y) = 1


If x=-2,1,2 and the y intercept is y=-8 for y=ax^3+bx^2+cx+d, what is a, b, c and d