A curve is defined by the parametric equations x = 3 - 4t, and y = 1 + 2/t. Find dy/dx in terms of t.

At first glance, this looks quite tricky, as usually when we are asked to find dy/dx, we have one equation, but here we have 2.So in this case, we need to use the statement that dy/dx = (dy/dt) * (dt/dx)Then, we just need to find dy/dt and dy/dx.dy/dt = -2/t^2dx/dt = -4, and therefore dt/dx = -1/4So, (dy/dt)(dt/dx) = (-2/t^2)(-1/4)= 1/2t^2.

WM
Answered by Wesley M. Maths tutor

10630 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Consider the function f(x) = 2/3 x^3 + bx^2 + 2x + 3, where b is some undetermined coefficient:


a curve is defined by y=2x^2 - 10x +7. point (3, -5) lies on this curve. find the equation of the normal to this curve


solve sin(2x)=0.5. between 0<x<2pi


differentiate y=(5x-2)^5


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning