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The triangle ABC is such that AC=8cm, CB=12cm, angle ACB=x radians. The area of triangle ABC = 20cm^2. Show that x=0.430 (3sf)

From the equation of the area of a triangle,
Area = 1/2 ACCBsin(C)
20 = 1/2 * 8 *12 * sin(x)
=> sin(x) = 0.416666...
=> x = 0.430 to 3sf

LD

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