Find where the graph of y=3x^2+7x-6 crosses the x axis
At the point where the line crosses the x axis, y=0
3x^2+7x-6=0
(3x-2)(x+3)=0
3x-2=0 or x+3=0
giving x=2/3 and x=-3
so the line crosses the x axis at (2/3,0) and (-3,0)
DB
At the point where the line crosses the x axis, y=0
3x^2+7x-6=0
(3x-2)(x+3)=0
3x-2=0 or x+3=0
giving x=2/3 and x=-3
so the line crosses the x axis at (2/3,0) and (-3,0)
