What is [(x+1)/(3x^(2)-3)] - [1/(3x+1)] in its simplest form?
First simplify the expression; 3x^(2)-3 to get;
[(x+1)/3(x^(2)-1)] - [1/(3x+1)]
Using the fact that x^(2)-1 is the difference of two squares, we can simplify it to;
[(x+1)/3(x+1)(x-1)] - [1/(3x+1)]
which simplifies to;
[1/3(x-1)] - [1/(3x+1)]
finally adding the two gives
4/3(x-1)(3x+1)
FO
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