What is [(x+1)/(3x^(2)-3)] - [1/(3x+1)] in its simplest form?
First simplify the expression; 3x^(2)-3 to get;
[(x+1)/3(x^(2)-1)] - [1/(3x+1)]
Using the fact that x^(2)-1 is the difference of two squares, we can simplify it to;
[(x+1)/3(x+1)(x-1)] - [1/(3x+1)]
which simplifies to;
[1/3(x-1)] - [1/(3x+1)]
finally adding the two gives
4/3(x-1)(3x+1)
FO
Related Maths A Level answers
All answers ▸Find the derivative with respect to x and the x-coordinate of the stationary point of: y=(4x^2+1)^5
A girl saves money over 200 weeks. She saves 5p in Week 1, 7p in Week 2, 9p in Week 3, and so on until Week 200. Her weekly savings form an arithmetic sequence. Find the amount she saves in Week 200. Calculate total savings over the 200 week period.
Find the integral of ln(x)
A curve has an equation: (2x^2)*y +2x + 4y – cos(pi*y) = 17. Find dy/dx