What is [(x+1)/(3x^(2)-3)] - [1/(3x+1)] in its simplest form?
First simplify the expression; 3x^(2)-3 to get;
[(x+1)/3(x^(2)-1)] - [1/(3x+1)]
Using the fact that x^(2)-1 is the difference of two squares, we can simplify it to;
[(x+1)/3(x+1)(x-1)] - [1/(3x+1)]
which simplifies to;
[1/3(x-1)] - [1/(3x+1)]
finally adding the two gives
4/3(x-1)(3x+1)
FO
Related Maths A Level answers
All answers ▸Integrate (x^2+4x+13)/((x+2)^2)(x-1) dx by using partial fractions
Differentiate x^x
Find the area of the region, R, bounded by the curve y=x^(-2/3), the line x = 1 and the x axis . In addition, find the volume of revolution of this region when rotated 2 pi radians around the x axis.
How do I simply differentiate and what does a differential mean?