Where z is a complex number, what is the cartesian form of |Z-2+3i| = 1?

Z is simply a general complex number, which can be written as Z = x+iyHere |Z-2+3i| = 1 can be written as |Z-(2-3i)| = 1, which is just an expression for every Z whose distance from the point (2,-3i) is equal to 1.We can solve this by recalling that Z = x+iy, and so we can seperate the real and imaginary parts in the modulus function. i.e. 1 = |(x-2) + i(y+3)| Evaluating the modulus now becomes simple as we calculate the magnitude using pythagoras. This Yields:12 = (x-2)2 + (y+3)2 , which is the cartesian form!we recognise this as the equation of a circle, with centre (2,-3) and radius 1. 

MH
Answered by Mark H. Maths tutor

10150 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The curve C has the equation y = 2x^2 -11x + 13. Find the equation of the tangent to C at the point P (2, -1).


Two lines have equations r_1=(1,-1,2)+a(-1,3,4) and r_2=(c,-4,0)+b(0,3,2). If the lines intersect find c:


7^6 x 7^3


Prove the identity (sin2x)/(1+(tanx)^2) = 2sinx(cosx)^3


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning