Solve for 0<=θ<π, the equation sin3θ-(sqrt3)cosθ=0 (C2)
Rearrange the equation to give sin3θ=(sqrt3)cos3θ, then divide through by cos3θ to give sin3θ/cos3θ=sqrt3. We know from our trig identities that sinx/cosx=tanx, so our equation now becomes tan3θ=sqrt3. Use your calculator to find 3θ, I got 3θ=π/3, so θ=π/9 which is within our range for θ.
BH
Related Maths A Level answers
All answers ▸What is a confidence interval?
A curve has equation y = 20x - x^2 - 2x^3 . The curve has a stationary point at the point M where x = −2. Find the x- coordinate of the other stationary point of the curve
Find f''(x), Given that f(x)=5x^3 - 6x^(4/3) + 2x - 3
Integrate 2x^5 + 7x^3 - (3/x^2)