Answers>Maths>A Level>Article

Solve for 0<=θ<π, the equation sin3θ-(sqrt3)cosθ=0 (C2)

Rearrange the equation to give sin3θ=(sqrt3)cos3θ, then divide through by cos3θ to give sin3θ/cos3θ=sqrt3. We know from our trig identities that sinx/cosx=tanx, so our equation now becomes tan3θ=sqrt3. Use your calculator to find 3θ, I got 3θ=π/3, so θ=π/9 which is within our range for θ.

Answered by Becky H. • Maths tutor

10075 Views

See similar Maths A Level tutors

Solve for 0<=θ<π, the equation sin3θ-(sqrt3)cosθ=0 (C2)

Related Maths A Level answers

Separate (9x^2 + 8x + 10)/(x^2 + 1)(x + 2) into partial fractions.

Find ∫(x^3+x^2+6)dx.

Find the max/min value of the function: f(x) = 5x^2 - 20x + 15

Let N be an integer not divisible by 3. Prove N^2 = 3a + 1, where a is an integer